20 lines
452 B
Python
20 lines
452 B
Python
def step(digest,prev_m):
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k = 0
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while True:
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rem = ((digest ^ prev_m) + k * 256) % 129
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if rem == 0:
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return ((digest ^ prev_m) + k * 256) / 129
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else:
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k = k + 1
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def answer(digest):
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prev = 0
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message = []
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for index, num in enumerate(digest):
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if index == 0:
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message.append(step(num,0))
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else:
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message.append(step(num,message[-1]))
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return message
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