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finish recursion function, complete functionality

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This commit is contained in:
Orien Vandenbergh 2016-08-29 18:16:22 -06:00
parent b8ebc7ff78
commit 87f62712ea
1 changed files with 10 additions and 14 deletions
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24
python/foobar/three/interrogation.py
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@ -13,31 +13,27 @@ def answer(minions):
optimal = [ [], 0 ]
for i,minion in enumerate(minions):
recurse_minions([i],minions,1-probabilityOf(minion),minion[0])
optimal = goDeeper(optimal,[i],minions,1-probabilityOf(minion),minion[0])
return optimal[0]
def recurse_minions(used,minions,pn,t):
global optimal
def goDeeper(optimal,used,minions,pn,t):
"""My recursion function to evaluate all the combinations of interrogation orders"""
for i, minion in enumerate(minions):
try:
used.index(i)
next
except ValueError:
# Counterintuitive warning: ValueError indicates that 'i' does not
# exist within the list of currently used minions. This means that
# we process this minion. Lack of ValueError indicates that this
# minion has already been processed.
if i not in used:
p = pn*(1-probabilityOf(minion))
time = t + (pn*minion[0])
curr = used+[i]
if len(curr) == len(minions):
if len(optimal[0])>0:
if time < optimal[1]:
optimal[0] = curr
optimal[1] = time
optimal = [ curr, time ]
else:
optimal = [ curr, time ]
else:
recurse_minions(curr,minions,p,time)
optimal = goDeeper(optimal,curr,minions,p,time)
return optimal
def probabilityOf(minion):
return ((1.0*minion[1])/minion[2])